解题思路:
1. 遍历数组,找出当前commonprefix下一个str的commonprefix。
2. 查看数组里所有的变量的第i位置上的字符相等否
public String longestCommonPrefix(String[] strs) { String prefix = ""; if(strs.length == 0) return prefix; prefix = strs[0]; for(int i = 1; i < strs.length && prefix.length() > 0; i++){ int j = 0; while(j < prefix.length() && j < strs[i].length() && prefix.charAt(j) == strs[i].charAt(j)) j++; prefix = prefix.substring(0, j); } return prefix; }
public String longestCommonPrefix(String[] strs) { String res = ""; if(strs.length == 0) return res; res = strs[0]; for(int i = 0; i < res.length(); i++){ for(int j = 1; j < strs.length; j++){ if(i >= strs[j].length() || strs[j].charAt(i) != res.charAt(i)){ return res.substring(0, i); } } } return res; }
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